-16x^2+112x+70=0

Solution for -16x^2+112x+70=0 equation:

-16x^2+112x+70=0

a = -16; b = 112; c = +70;
Δ = b2-4ac
Δ = 1122-4·(-16)·70
Δ = 17024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17024}=\sqrt{64*266}=\sqrt{64}*\sqrt{266}=8\sqrt{266}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-8\sqrt{266}}{2*-16}=\frac{-112-8\sqrt{266}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+8\sqrt{266}}{2*-16}=\frac{-112+8\sqrt{266}}{-32}
$